Web23 okt. 2024 · Correct Answer - C a, b, c, d a, b, c, d are in GP a = a, b = ar, c = ar2, d = ar3 a = a, b = a r, c = a r 2, d = a r 3 b + c = ar + ar2 = ar(1 + r) b + c = a r + a r 2 = a r ( 1 + r) (b + c)2 + a2r2(1 + r2 + 2r) ( b + c) 2 + a 2 r 2 ( 1 + r 2 + 2 r) = a2r2 + a2r4 + 2a2r3 = a 2 r 2 + a 2 r 4 + 2 a 2 r 3 = a ⋅ ar2 + ar ⋅ ar3 + a2r3 + a2r3 = a ⋅ WebSolution: Since, a,b,c and d are in GP. ∴ b2 = ac,c2 = bd and ab = cd ⇒ bc = ad...(i) Now, (a +b +c +d)2 = (a +b)2 + (c +d)2 +2(a +b)(c+ d) = (a +b)2 +(c +d)2 +2(ac+ ad+ bc +bd) …
a,b,c,d are in GP are in ascending order such a+d=112 and b+c…
Web8 aug. 2024 · If a, b, c, d, e are in G.P., then e/c equals : (a) d/b (b) c/b (c) b/a (d) d/c bitsat Share It On 1 Answer +1 vote answered Aug 8, 2024 by Aarju (69.8k points) selected Aug 8, 2024 by faiz Best answer Correct option (a) d/b Explanation: Let a, b, c, d, e be in G.P., with common ratio r. ← Prev Question Next Question → Find MCQs & Mock Test Web8 mrt. 2024 · If a b c d are in GP then prove that bc = ad See answers Advertisement Ushan12345 b^2=ac c^2=bd then, b^2 × c^2 = abcd bc×bc= ad×bc bc=ad where is the … cheapest north carolina car insurance
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Web30 mrt. 2024 · We have (a+bx)/ (a−bx) = (b+cx)/ (b−cx) = (c+dx)/ (c − dx) & we want to show that a, b, c, d are in G.P. Taking (a+bx)/ (a−bx) = (b+cx)/ (b−cx) = (c+dx)/ (c − dx) Applying componendo dividendo (a + bx + a − bx)/ ( (a + bx) − (a−bx)) = (b + cx + (b − cx))/ (b + cx − (b − cx)) = (c + dx + (c − dx))/ (c + dx − (c − dx)) (a + a + bx − bx)/ (𝑏𝑥+ bx − … WebIf a, b, c, d are in G.P., then ( (a2 +b2 + c2) (b2+c2+d2)/ (ab+bc +cd)2)= Q. If a,b,c,d are in G.P ., then (ab+bc+cd)2(a2+b2+c2)(b2+c2+d2) = 1736 31 Sequences and Series Report Error A 1 B 2 C 3 D 5 Solution: b = ar,c = ar2,d = ar3 ∴ a2 +b2 +c2 = a2(1+r2 +r4) b2 +c2 +d2 = a2r2 (1+r2 + r4) ab+bc+ cd = a2r(1+ r2 + r4) WebClick here👆to get an answer to your question ️ If a,b,c are in AP and a,b,d are in GP then a,(a - b),(d - c) are in Solve Study Textbooks Guides Join / Login cvs crowley rd crowley tx